Question

sec^ 6 ∅= tan ^ 6 ∅+3 tan² ∅· sec²∅+ 1

Answer 1

Hey !!!

sec^6¢ = ( 1 + tan²¢ )^³

•°• sec²¢ = 1 + tan²¢

we know that ,

(a + b )³ = a³ + b³ + 3ab ( a + b )

like that ,

{1 + tan²¢ )³ = 1³+( tan²¢)² + 3×tan²¢*1 ( 1 + tan²¢ )

1 + tan^6¢

{( 1 + tan^6¢ + 3tan²¢ (sec²¢ ) }

1 + tan^6¢ + 3tan²¢ sec²¢

tan^6¢+ 3tan²¢ sec²¢ + 1 RHS prooved

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Hope it helps you !!

@Rajukumar111

Answer 2

Please help me to become brainlist and I hope that you will understand easily