Math, asked by prabhakarreddy4540, 3 months ago

Sec^6theta =tan^6theta +3×tan^2theta×sec^2theta +1

Answers

Answered by mathdude500
0

Answer:

 {sec}^{6} x =  { {(sec}^{2}x) }^{3}  =  {(1 +  {tan}^{2}x) }^{3}   \\  = 1 +  {tan}^{6} x + 3 {tan}^{2} x(1 +  {tan}^{2} x) \\  = 1 +  {tan}^{6} x + 3 {tan}^{2} x \:  {sec}^{2} x

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