Sec(90-0)cosec0-tan(90-0)cot0+cos square 25 +cos sqaure 25 the whole divide by 3×tan27×tan63
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( 1 + 2 cos²25 ) / 3
Step-by-step explanation:
[ sec ( 90 - Ф ) cosec Ф - tan ( 90 - Ф ) cot Ф + cos²Ф + cos²Ф ) ] / ( 3 tan 27 . tan 63 )
Use this carefully :
sec ( 90 - Ф ) = cosec Ф
tan ( 90 - Ф ) = cot Ф
= > [ cosec Ф cosec Ф - cot Ф cot Ф + 2 cos² 25 ] / ( 3 tan ( 90 - 63 ) tan 63 )
= > [ cosec²Ф - cot²Ф + 2 cos² 25 ] / ( 3 cot 63 tan 63 )
Use cosec²Ф - cot²Ф = 1
Use cot Ф tan Ф = 1
= > [ 1 + 2 cos²25 ] / ( 3 × 1 )
= > ( 1 + 2 cos²25 ) / 3
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