Question

sec(90-A)cosec(90-A)is equal to sec square A cotA​

Answer 1

Sec(90°-A)cot(90°A)

1/cos(90•-A)×1/sin(90•-A)

1/sinA×1/cosAcosA

Multiply by cosa up and down of the expression

Cos A/(cos A ×cos A) × 1/sin A

Then ,

Sec^2 A.cot A

Hence proved