Question

sec(90-theta)cosec theta -tan(90-theta) cot theta+cos^2 25 +cos^2 65/3tan 27 tan 63 =?

Answer 1

Answer:

Step-by-step explanation:

Sec(90-A) cosec-tan(90-A) cotA+cos^2 25+cos^2 65/3tan27.tan63

CosecA.cosecA-cotA.cotA+sin^2 65+cos^2 65/3cot63.tan63

(Cosec^2A-cot^2A)+(sin^2A+cos^2A)/3cot63.tan63

1+1/3

2/3

Answer 2

Refers to attachment ♡~