Math, asked by aslu1328, 1 year ago

sec(90-theta)cosec theta -tan(90-theta) cot theta+cos^2 25 +cos^2 65/3tan 27 tan 63 =?

Answers

Answered by rashmikukreti1996
22

Answer:

Step-by-step explanation:

Sec(90-A) cosec-tan(90-A) cotA+cos^2 25+cos^2 65/3tan27.tan63

CosecA.cosecA-cotA.cotA+sin^2 65+cos^2 65/3cot63.tan63

(Cosec^2A-cot^2A)+(sin^2A+cos^2A)/3cot63.tan63

1+1/3

2/3

Answered by ItzRadhika
6

Refers to attachment ~

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