sec(90-theta)cosec theta -tan(90-theta) cot theta+cos^2 25 +cos^2 65/3tan 27 tan 63 =?
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Answer:
Step-by-step explanation:
Sec(90-A) cosec-tan(90-A) cotA+cos^2 25+cos^2 65/3tan27.tan63
CosecA.cosecA-cotA.cotA+sin^2 65+cos^2 65/3cot63.tan63
(Cosec^2A-cot^2A)+(sin^2A+cos^2A)/3cot63.tan63
1+1/3
2/3
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