Math, asked by nandinivyas1125, 1 month ago

sec(90-theta)cosec theta-tan(90-theta)cot theta +cos235°+cos255°/tan5°tan15°tan45°tan75°tan85°

plz give the answer with solution...!!

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Answered by Anonymous

5

Answer:

l hope it will help u ☺️☺️☺️

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