Question

sec A - 1 / sec A + 1 = 1 - cos A / 1+ cos A​

Answer 1

Step-by-step explanation:

According to question,

secA+tanA

1

−

cosA

1

=

cosA

1

−

secA−tanA

1

⟹

secA+tanA

1

+

secA−tanA

1

=2secA

Solving LHS,

⟹

(secA+tanA)(secA−tanA)

secA−tanA+secA+tanA

⟹

sec

2

A−tan

2

A

2secA

⟹

1

2secA

⟹2secA = RHS

Hence proved

Answer 2

Answer:

sec means

1/cos;

1/cosA-1 / 1/cosA+1

cosA-1/cosA/cosA+1/cosA

cosA-1/cosA*cosA/cosA+1

Step-by-step explanation:

hope it helps you

{sec^2-tan^2=1}

{sec^2=1-tan^2}// we write like that