Question

sec A-1/sec A +1=1- cos A/1+cos A
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Answer 1

i hope this helps you solve the problem plz mark as brainliest

Answer 2

LHS=

(secA-1)/(secA+1)=

[secA=1/cosA]

(1/cosA -1)/(1/cosA+1)

{(1-cosA)/cosA}×{cosA/1+cosA}

1-cosA/1+cosA.

proved