Math, asked by VaibhavDixit, 1 year ago

sec A -1 ÷ sec A+1 =(cot A-cosec A)^2

Answers

Answered by mysticd
4
rhs = (cotA- cosecA)^2

= [cosA/sinA -1/sinA]^2
=[(cosA-1)/sinA]^2

=(cosA-1)^2/sin^2A

=(1-cosA)^2/[1- cos^2A]

=[(1-cosA)(1-cosA)]/[(1+cosA)(1-cosA)]

=(1-cosA)/(1+cosA)
divide numerator and denominator with cosA

=[1/cosA - cosA/cosA]/[1/cosA + cosA/cosA]

=[1/cosA -1]/[1/cosA +1]
=(secA -1)/(secA +1)
=lhs

mysticd: ur welcome
mysticd: thank you selecting as brainliest
Similar questions