sec A (1_sin A)(1_sin A)(sceA+tan A
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Solution
→ secA(1 - sinA)(secA + tanA)
We know secA = 1/cosA and tanA = sinA/cosA.
→ 1/cosA × (1 - sinA)(1/cosA + sinA/cosA)
→ 1/cosA × (1 - sinA)(1 + sinA)/cosA
Since (1 - sinA)(1 + sinA) = 1² - sin²A.
→ 1/cosA × (1 - sin²A)/cosA
We know that 1 - sin²A = cos²A
→ 1/cosA × cos²A/cosA
→ cos²A/cos²A = 1
Hence required answer is 1.
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