sec A (1 - sin A) (sec A + tan A) = 1
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Answer:
L.H.S=secA(1−sinA)(secA+tanA)=(secA−
cosA
sinA
)(secA+tanA)
=(secA−tanA)(secA+tanA)
=sec
2
A−tan
2
A
Putting if tan
2
A+1=sec
2
A−
we get L.H.S=1+tan
2
A−tan
2
A=1
⇒L.H.S=R.H.S
Step-by-step explanation:
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