Math, asked by anshumodi9416, 4 days ago

sec A( 1 - sin A)(sec A + tan A)= ​

Answers

Answered by siwachprachi70
0

L.H.S=secA(1−sinA)(secA+tanA)=(secA−

cosA

sinA

)(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec

2

A−tan

2

A

Putting if tan

2

A+1=sec

2

A−

we get L.H.S=1+tan

2

A−tan

2

A=1

⇒L.H.S=R.H.S

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