Question

sec A (1-sin A) (sec A+ tanA ) =)​

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

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Prove that :

$secA (1 - sinA) (secA + tanA)= 1$

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$LHS = sec A (1 - sinA) (secA + tanA) \\ = \frac{1}{cosA}(1 - sinA) (\frac{1}{cosA} + \frac{sinA}{cosA}) \\ = (\frac {1 - sinA}{cosA})(\frac {1 - sinA}{cosA}) \\ = \frac {1² - sin²A}{cos²A} \\ = \frac{cos²A}{cos²A} \\ = 1 = RHS$