sec A. √1-sin²A=? answer fastly
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your answer dear...........see attachment
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Answered by
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Answer:
(1-sinA/1+sinA)
(1-sin A)² / ( 1-sin²A)
1+sin²A-2sinA/ cos²A
sec²A + tan² A - 2 tanA.secA
(secA-tanA)²
So there must be some mistake in question…..plz check
Then square root of L.H.S =
secA-tanA
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