Question

sec A (1-sinA) ( sec A + tan A ) = 1
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Answer 1

Answer:

1/cos(1-sinA)(1/cos+sin/cos)=1

1/cos(1-sinA)(1+sinA/cosA)=1

1/cos²A(1-sin²A)=1

cos²A/cos²A=1

1=1

Answer 2

Answer:

(sec A - sec A×sinA)(sec A + tan A)

(sec A - 1/cos A × sin A)(sec A + tan A)

(sec A - tan A)(sec A + tan A)

(sec^2A - tan^2A) = 1 = R.H.S