Math, asked by chitracharan15, 9 months ago

sec A(1 -sinA) (secA+tan A) =1

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Answered by petertang0496

10

Answer:Sec A(1 -sinA) (secA+tan A) =1

L.H.S.=(1/cosA)(1-sinA)(1/cosA+sinA/cosA)

=(1/cosA)(1-sinA)((1+sinA)/cosA))

=(1/cosA)((1+sinA)/cosA))(1-sinA)

=((1+sinA)/cos²A)(1-sinA)

=((1+sinA)/(1-sin²A))(1-sinA)

=((1+sinA)/((1+sinA)(1-sinA)))(1-sinA)

=1

=R.H.S.

Step-by-step explanation:

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