sec A(1 -sinA) (secA+tan A) =1
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Answer:Sec A(1 -sinA) (secA+tan A) =1
L.H.S.=(1/cosA)(1-sinA)(1/cosA+sinA/cosA)
=(1/cosA)(1-sinA)((1+sinA)/cosA))
=(1/cosA)((1+sinA)/cosA))(1-sinA)
=((1+sinA)/cos²A)(1-sinA)
=((1+sinA)/(1-sin²A))(1-sinA)
=((1+sinA)/((1+sinA)(1-sinA)))(1-sinA)
=1
=R.H.S.
Step-by-step explanation:
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