Question

ਜੇਕਰ sec A =13/12 ਤਾ sinA ਦਾ ਮੁॅਲ ਪਤਾ ਕਰੋ ​

Answer 1

$\sec a = \frac{13}{12} \\ \\ \cos a = \frac{12}{13} \\ \\ \sin a = \sqrt{1 - {cos}^{2}a } \\ \\ = \sqrt{1 - \frac{144}{169} } \\ \\ = \sqrt{ \frac{25}{169} } \\ \\ = \frac{5}{13}$