Question

(Sec A by secA-1)+ (SecA by sec A+1)

Answer 1

Hi ,

SecA/ ( secA - 1 ) + secA / ( secA+1)

= SecA[ 1/( secA-1) + 1/( secA+1 )]

= SecA [ ( secA+1 + secA-1 )/(sec²A-1²]

= SecA( 2secA ) / tan² A

= 2sec² A/ tan² A

= ( 2/cos² A ) / ( sin² A/cos² A )

= 2 /sin² A

= 2cosec²A

I hope this helps you.

:)