Math, asked by agarwalpurvi7941, 8 months ago

Sec A-Cos A=5 then what is the value of sec²A-cos²A=?

Answers

Answered by Anonymous

0

Step-by-step explanation:

SecA-CosA = 5

SecA + CosA = √(SecA-CosA)²+4SecA*CosA

= √25+4 = √29

Sec²A-Cos²A = 5√29

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