(sec A- cos A)(cot A+ tan A)=tan A secA
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Answer:
sec A - cos A ia a answers
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Answer: Hey friend here's your answer!
Step-by-step explanation:
LHS = (secA-cosA)x (cotA+tanA)
= (1/cosA - cosA) x (cosA/sinA + sinA/cosA)
= (1 - cos^2 A)/cosAx ((sin^2 A +cos^2 A) / sinAcosA)
= ((sin^2 A) / cosA) x( 1 / sinAcosA)
= sinA / cos^2 A
= (sinA/cosA) x (1/cosA)
= tanA secA
RHS = tanA secA
:. LHS=RHS
Hence proved
I hope it helps you friend!
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