( sec a + cos a )(sec a - cos a)= tan ^2 a + sin^2 a prove
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Answered by
41
Hi Friend !!
Here is ur answer !!!
(sec a + cos a)(sec a - cos a)
= sec²a - cos²a
= 1/cos²a - cos²a
= 1-cos^4 a / cos²a
= 1+cos²a(sin² a) / cos²a
= 1+cos²a/cos²a + sin²a/cos²a
= sin²a+tan²a
HENCE PROVED
Hope it helps u : )
Here is ur answer !!!
(sec a + cos a)(sec a - cos a)
= sec²a - cos²a
= 1/cos²a - cos²a
= 1-cos^4 a / cos²a
= 1+cos²a(sin² a) / cos²a
= 1+cos²a/cos²a + sin²a/cos²a
= sin²a+tan²a
HENCE PROVED
Hope it helps u : )
Answered by
15
Answer:
Step-by-step explanation:
day.
Brainly.in
What is your question?
(sec a + cos a)(sec a - cos a)
= sec²a - cos²a
= 1/cos²a - cos²a
= 1-cos^4 a / cos²a
= 1+cos²a(sin² a) / cos²a
= 1+cos²a/cos²a + sin²a/cos²a
= sin²a+tan²a
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