Question

Sec A - tan A = 1/√3 find sec A tan A

Answer 1

given, secA-tanA=1/√3.......(1)
since sec²A-tan²A=1
(secA+tanA)(secA-tanA)=1
(secA+tanA)×1/√3=1
secA+tanA=√3.....(2)
(1)+(2)
2secA=4/√3
secA=2/√3
and tanA=√3-2/√3=1/√3
therefore secA tanA=2/√3×1/√3=2/3(ans)

Answer 2

Hope this helps...........

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