Question

(Sec a+tan a+1)/(sec a-tan a+1)

Answer 1

Solution

→ (secA + tanA + 1)(secA - tanA + 1)

This can be written as follows:

→ (secA + 1 + tanA)(secA + 1 - tanA)

→ (secA + 1)² - (tanA)²

→ sec²A + 1 + 2 secA - tan²A

→ (sec²A - tan²A) + 2 secA + 1

→ 1 + 1 + 2 secA

→ 2(1 + secA)

Hence required answer is 2(1 + secA).