Question

(Sec A + Tan A - 1 )( Sec A - Tan A + 1)​

Answer 1

Answer:

let try

Step-by-step explanation:

=Sec^2A-SecA TanA+SecA+TanA SecA-Tan^2A+TanA-SecA+TanA-1

=(Sec^2A-Tan^2A)+2TanA-1

=1+2TanA-1=2TanA

Answer 2

$(secA + tanA - 1)(secA - tanA + 1) \\ \\ = ( \frac{1 + sinA - cosA}{cosA} )( \frac{1 - sinA + cosA}{cosA} ) \\ \\ = \frac{ {1}^{2} - ( {sinA - cosA)}^{2} }{ {cos}^{2}A } \\ \\ = \frac{2sinacosA}{ {cos}^{2}A } \\ \\ = 2tanA$