Math, asked by kumargulshan7923, 11 months ago

Sec a+tan a =1/sec a- tan a

Answers

Answered by patelkhushi08640

1

sec2 a -tan2 a = 1

((sec a-tan a)(sec a+ tan a) )/(seca -tan a)=1 /(sec a-tan a)

Therefore

sec a +tan a= 1/(seca -tan a)

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