Math, asked by sshivajyNatVIS, 1 year ago

Sec A+ tan A= 1/sec A_ tan A

Answers

Answered by ShivajiK
0
sec²A – tan²A = 1
( secA + tanA) × ( secA – tanA) = 1
secA + tanA = 1 / ( secA – tanA )
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