( sec a + tan a) (1 - sin) =
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Hello
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Given us,
( secA + tanA ) ( 1 - sinA )
we know that
secA = 1/cosA
tanA = sins/cosA
now
( 1 /cosA + sinA /cosA ) ( 1 - sinA )
= ( 1 + sinA ) ( 1 - sinA )/ cosA
= 1² - sin²A / cosA
= cos²A / cosA
= cosA
RHS
thanks
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