Question

( sec a + tan a) (1 - sin) =​

Answer 1

Answer:

Hello

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Given us,

( secA + tanA ) ( 1 - sinA )

we know that

secA = 1/cosA

tanA = sins/cosA

now

( 1 /cosA + sinA /cosA ) ( 1 - sinA )

= ( 1 + sinA ) ( 1 - sinA )/ cosA

= 1² - sin²A / cosA

= cos²A / cosA

= cosA

RHS

thanks