Question

(Sec A+tan A) (1 - Sin A)​

Answer 1

⇒(Sec A+tan A) (1 - Sin A)​

⇒(1/cosA +sinA/cosA) (1-SinA)

⇒(1+ SinA)(1-SinA)/CosA

⇒(1-Sin^2 A)/CosA

⇒Cos^2 A/CosA

⇒CosA

⇒

Answer 2

${ \sec(a) + \tan(a) }(1 - \sin(a) \ \\ = \ ( \frac{1}{ \cos(a) } + \frac{ \sin(a) }{ \cos(a) } ) (1 - \sin(a) \\ = \frac{(1 + \sin(a)) (1 - \sin(a) }{ \cos(a) } \\ = \frac{1 - { \sin}^{2}(a) }{ \cos(a) } \\ = \frac{ { \cos }^{2}(a) }{ \cos(a) } \\ = \cos(a) (ans)$

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