Question

(sec A + tan A) (1 - sin A) =


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Answer 1

$\huge{\mathcal{\underline{\green{SOLUTION}}}} </p><p></p><p>$

$(sec A + tan A) (1 - sin A)$

$= ( \frac{1}{cos A} + \frac{ sinA}{cos A} )(1 - sin A)$

$= \frac{(1 + sin A)}{cos A} (1 - sin A)$

$= \frac{1 - {sin}^{2} A }{cos A}$

$= \frac{ {cos}^{2}A}{cosA}$

$= cosA$

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Answer 2

Answer is given in the pic.