(sec a + tan a ) (1 - sin a ) =
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Answered by
1
Answer:
Hello
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Given us,
( secA + tanA ) ( 1 - sinA )
we know that
secA = 1/cosA
tanA = sins/cosA
now
( 1 /cosA + sinA /cosA ) ( 1 - sinA )
= ( 1 + sinA ) ( 1 - sinA )/ cosA
= 1² - sin²A / cosA
= cos²A / cosA
= cosA
RHS
thanks
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Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
sec A+tan A)(1-sinA)
=(1/cos A + sin A/cos A)(1-sinA)
=[(1+sinA)/cosA](1-sinA)
=(1+sinA)(1-sinA)/cosA
=(1-sin^2 A)/cosA
=(cos^2 A)/cos A
=cos A
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