Question

(sec A+ tan A) (1-sin A) =​

Answer 1

[ ( secA + tanA ) ( 1 - sinA ) ] [ ( 1 + sinAcosA ) ( 1 - sinA ) ] 1 - sin2AcosA = cos2AcosA cosA Hence, the answer is cosA

Answer 2

$\sf \large \mathfrak\color{purple}Solution$


$\sf \large \bigg (secA + tanA \bigg) \bigg(1 - sinA \bigg)$


$\sf \implies \large \bigg( \frac{1}{cosA} + \frac{sinA}{cosA} \bigg) \bigg (1 - sinA \bigg)$


$\sf \implies \large \frac{ \bigg(1 + sinA \bigg) \bigg(1 - sinA \bigg)}{cosA}$


$\sf \large \implies \frac{1 - {sin}^{2}A }{cosA}$


$\sf \large \implies \frac{c {cos}^{2}A }{cosA} = cosA$