(sec A +tan A) (1 -sin A) =
Answers
Answered by
0
Answer:
(secA+tanA)(1−sinA)
=(
cosA
1
+
cosA
sinA
)(1−sinA)
=(
cosA
1+sinA
)(1−sinA)
=
cosA
(1+sinA)(1−sinA)
=
=
cosA
(1−sin
2
A)
=
cosA
cos
2
A
=cosA
∴(secA+tanA)(1−sinA)=cosA
Hence, the answer is cosA.
Answered by
0
Answer:
cosA
Step-by-step explanation:
(1/cosA+sinA/cosA)(1-sinA)=(1+sinA)(1-sinA)/cosA=1-sin^2A/cosA=cos^2A/cosA=cosA
Similar questions