Question

(sec A + tan A)(1- sin A)=​

Answer 1

$\sf \: \bigg(secA + tanA \bigg) \bigg(1 - sinA \bigg)$

$\implies \sf \large\bigg( \frac{1}{cosA} + \frac{sinA}{cosA} \bigg) \bigg(1 - sinA \bigg)$

$\implies \sf \large \frac{ \bigg(1 + sinA \bigg) \bigg(1 - sinA \bigg)}{cosA}$

$\implies \sf \large \frac{1 - {sin}^{2}A }{cosA}$

$\implies \sf \large \frac{ {cos}^{2}A }{cosA} = cosA$

Answer 2

Answer:

Refers to above attachment.......