Math, asked by devyanshurathore583, 2 months ago

( sec A + tan A ) ( 1 - sin A )

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Answered by sandy1816

2

$(seca + tana)(1 - sina) \\ = ( \frac{1 + sina}{cosa} )(1 - sina) \\ = \frac{1 - {sin}^{2}a }{cosa} \\ = \frac{ {cos}^{2}a }{cosa} \\ = cosa$

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