(sec A + tan A) (1 - sin A)
a. sec a
b. sina
c.coseca
d. cosa
Answers
Answered by
2
(secA+tanA)(1-sinA)
=> secA-secAsinA +tanA - tanAsinA
=> secA -tanA +tanA -sin²A/cosA
=>1/cosA -sin²A/cosA
=>(1-sin²A)/cosA
=>cos²A/cosA
=>cosA
{1-sin²A = cos²A
secAsinA = tanA}
The correct option is D. cosA
Cheers!
Answered by
0
Step-by-step explanation:
(sec A+ tanA)1-sinA
(1÷cosA+sinA÷cosA )(1-sinA)
1+sinA÷cosA×1-sinA
1-sin2A÷cosA
cos2A ÷cosA
cos A
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