Question

) (sec A + tan A) (1 - sin A) = COS A prove​

Answer 1

first we need to solve LHS

solving LHS,

(secA+tanA) (1-sinA)

(1/cosA+SinA/cosA) (1-sinA)

(1+sinA/cosA) (1-sinA)

using a²- b²=(a+b) (a-b) formula,

1-sin²a/cosA

using formula, sin²A+cos²A=1

so, 1-sin²A=cos²A

cos²A/cosA

= cosA which is equal to RHS

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