Math, asked by manugyamanasdutta296, 6 months ago

(Sec A + tan A) ( 1-SinA) =

Answers

Answered by saiyedfazil

2

(secA+ tanA ) (1-sinA)

( 1/cosA + sinA/cosA) ( 1-sinA)

( 1+sinA / cosA) (1-sinA)

apply a^2-b^2 in numerator

1^2 - SinA ^2/CosA (identity in numerator

CosA^2/CosA

CosA

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