(sec A+tan A) (1-SinA)
adarshkumarsingh7250:
plz help
Answers
Answered by
1
Step-by-step explanation:
[(secA+tanA)(1−sinA)]
⇒[(
cosA
1+sinA
)(1−sinA)]
⇒
cosA
1−sin
2
A
=
cosA
cos
2
A
⇒cosA
Hence, the answer is cosA.
Answered by
1
Answer:
cosA
Step-by-step explanation:
(1 / cosA + sinA/cosA ) ( 1 - sinA )
[( 1 + sinA/cosA)] ( 1 - sinA)
(1² - sin ² A)/cosA.................( since 1- sin²A=cosA)
cos²A/cosA
cosA. ( ANSWER)
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