Question

sec A+tan A-1/tan A-sec A+1=cos A/1-sin A​

Answer 1

Answer:

L.H.S=tanA−secA+1tanA+secA−1

=tanA−secA+1(tanA+secA)−(sec2A−tan2A)=tanA−secA+1(tanA+secA)(1−(secA−tanA))=tanA+1−secA(tanA+secA)(1−secA−tanA)

=secA+tanA

=cosA1+cosAsinA

=cosA1+sinA

R.H.S proved.

Step-by-step explanation:

I hope it will help you.

.

.

.

.

.

.

.

please mark me as a thanks

Answer 2

Answer:

L.H.S=

tanA−secA+1

tanA+secA−1

=

tanA−secA+1

(tanA+secA)−(sec

2

A−tan

2

A)

=

tanA−secA+1

(tanA+secA)(1−(secA−tanA))

=

tanA+1−secA

(tanA+secA)(1−secA−tanA)

=secA+tanA

=

cosA

1

+

cosA

sinA

=

cosA

1+sinA

R.H.S proved.