Question

(sec A – tan A)2 ( 1 + sin A) =
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Answer 1

Answer:

LHS=(secA−tanA) ²

$= ( \frac{1}{ \cos(a) } - \frac{ \sin(a) }{ \cos(a) } )^{2}$

$= \frac{1 - \sin(a) }{1 + \cos(a) }$

$\boxed{HENCE \: \: PROVED \: \: \: R.H.S}$