Question

sec A + tan A = 3 then sec A= ?

Answer 1

Hope u like my process
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Formula to be used ::
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=> Sec² A - Tan² A = 1

=> x² - y² = (x+y) (x-y)
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Given
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Sec A + Tan A = 3....... (1)
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So,

Sec² A - Tan² A = 1

$or. \: \: ( \sec(a) + \tan(a) )( \sec(a) - \tan(a) ) = 1 \\ \\ or. \: \: 3 \times ( \sec(a) - \tan(a) ) = 1 \\ \\ or. \: \: \sec(a) - \tan(a) = \frac{1}{3} .....(2)$

Now adding equation (1) and (2) we get,

Sec A + Tan A = 3
+ Sec A - Tan A = ⅓
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2 Sec A = 3 +⅓

or, Sec A = ½ × (9+1)/3 = ½× 10/3

or, Sec A = 5/3 ___answer__

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Hope this is ur required answer

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Answer 2

Answer:

Step-by-step explanation: