sec A + tan a = 3 then sec a equals to how much
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Formula to be used ::
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=> Sec² A - Tan² A = 1
=> x² - y² = (x+y) (x-y)
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Given
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Sec A + Tan A = 3....... (1)
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So,
Sec² A - Tan² A = 1
Now adding equation (1) and (2) we get,
Sec A + Tan A = 3
+ Sec A - Tan A = ⅓
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2 Sec A = 3 +⅓
or, Sec A = ½ × (9+1)/3 = ½× 10/3
or, Sec A = 5/3 ___answer__
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