Question

sec A + tan A =3 then secA=​

Answer 1

Answer:

5/3

Step-by-step explanation:

we know that, 1+tan^2A=sec^2A

(secA+tanA)(secA-tanA)=1

secA+tanA=1/secA-tanA

then,1/secA-tanA=3

then, secA-tanA=1/3

equation1+2

secA+tanA=3

secA-tanA=1/3

2secA=10/3

secA=10/3×1/2=5/3