(sec a +tan a) =7/5 then (sec a - tan a) =?
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Answered by
1
Given:
sec a + tan a =7/5
To find:
sec a - tan a =?
Using the identity:
sec^2a - tan^2a=1
=>(sec a + tan a)(sec a - tan a)=1
=>7/5(sec a - tan a)=1
=>sec a - tan a= 5/7
sec a + tan a =7/5
To find:
sec a - tan a =?
Using the identity:
sec^2a - tan^2a=1
=>(sec a + tan a)(sec a - tan a)=1
=>7/5(sec a - tan a)=1
=>sec a - tan a= 5/7
Answered by
0
seca+tana=7/5
(seca+tana)(seca-tana)/(seca-tana)=7/5
(sec²a-tan²a)/(seca-tana)=7/5
1/(seca-tana)=7/5
=>. seca-tana=5/7
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