Sec a + tan a=a find sec a and tan a
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sec a= a & tan a= 2a
Step-by-step explanation:
sec a + tan a =a
1/cos a + sin a / cos a = a
cos a + sin a / cos a = a .........(squaring on both sides)
cos^2 a + sin^2 a /cos^2 a = a^2
1/cos^2 = a^2 ..........(sin^2 + cos^2 = 1)
sec^2 a = a^2...........(1/ cos a = sec a).....taking square root
sec a = a
Now, sec a + tan a = a
a + tan a = a ......(sec a = a)
tan a = a + a
tan a = 2a
Therefore, sec a= a and tan a= 2a
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