Question

(Sec A+ Tan A) (Sec A-Tan A) = 1​

Answer 1

Answer:

sec2A-secAtanA+secAtanA-tan2A=1

sec2A-tan2A=1

1=1

Answer 2

Answer:

Yes, the above statement is correct.

Step-by-step explanation:

We know, (a + b) (a - b) = $a^{2} - b^{2}$

Here take sec A = a and tan A = b

⇒ $sec^{2}A - tan^{2} A$

And we know, $sec^{2}A = 1 + tan^{2} A$

So, $sec^{2}A - tan^{2} A$ = 1

∴ 1 = 1

Hence Proved