Question

= sec A-tan A
sec A + tan A​

Answer 1

Step-by-step explanation:

the question is

not clear

we know that,

sec^2A-tan^2A=1

Answer 2

Answer: 1

Step-by-step-explanation:

$(SecA-TanA)(SecA+TanA)$

$=Sec^{2}A-tan^{2}A$

$[(a+b)(a-b)=a^{2} b^{2}]$

$=1$

$[sec^{2}A- tan^{2} A=1]$