Math, asked by babluraieen219, 3 months ago

sec A - tan A upon sec A + tan A = 1-2 sec A tan A+ 2 tan square A

Answers

Answered by vaibhavpednekar267

2

Answer:

LHS=

secA+tanA

secA−tanA

=

secA+tanA

secA−tanA

×

secA−tanA

secA−tanA

=

sec

2

A−tan

2

A

sec

2

A−2secAtanA+tan

2

A

=1+tan

2

A−2secAtanA+tan

2

A

=1−2secAtanA+2tan

2

A

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