Question

(sec-cos)(cosec-sin)(tan+cot)=?​

Answer 1

$(sec - cos)(cosec - sin)(tan + cot) \\ = ( \frac{1 - {cos}^{2} }{cos} )( \frac{1 - {sin}^{2} }{sin} )( \frac{1}{sin \: cos} ) \\ = \frac{ {sin}^{2} {cos}^{2} }{sin \: cos} . \frac{1}{sin \: cos} \\ = \frac{ {sin}^{2} {cos}^{2} }{ {sin}^{2} {cos}^{2} } \\ = 1$