Question

(sec + cos )(sec - cos )​

Answer 1

=sec^2 theeta - cos^2 theeta

=1+tan^2 theeta-(1- sin^2 theeta)

=1+tan^2 theeta-1+sin^2 theeta

=tan^2 theeta+sin^2 theeta

Answer 2

Answer:

I think the Answer is:

sec ^2-cos^2

Step-by-step explanation:

Because,

(sec+cos ) (sec-cos)

= (sec-cos)^2

= (1/cos - cos) ^2

= (1-cos^2/cos)^2

= (sin^2/cos) ^2

= sin^2/cos ^2

= cot theta